JEE Main 2019 was released in late evening on www.jeemain.nic.in. Candidates willing to appear for the JEE Advanced Examination, will be required to get minimum marks in JEE Main to qualify for JEE Advanced 2019. NIT has also released the JEE Main Cut Off for the IIT JEE Advance examination. In the Joint Entrance Examination (JEE) Main held for admission in engineering colleges, 24 students secured 100 percentile.

Candidates must note that unlike previous years, this year cut off will be based on the NTA score, which is the percentage measure of students' performance. JEE Main 2019 cut off for JEE advance is being given below. Candidates note that the status of candidates passing through different categories will be available on their JEE Main 2019 Result window. Check your JEE Main 2019 result on www.jeemain.nic.in.

The exact number of candidates qualifying for JEE Advanced 2019 is not currently shared by the NTA. However, a rough estimate shows that more than 2.5 lakh candidates have qualified for JEE advance which is an entrance test for the Indian Institute of Technology or IIT.

All the candidates who are eligible for JEE advance will have to fill the online application form on the official website www.jeeadv.ac.in. Let us inform you that online application forms for JEE advance will open from May 3, 2019 and close on May 8, 2019. Candidates need to apply online and pay the fee.

The JEE Advanced 2019 exam was postponed due to General Election 2019, JEE Advance will now be held on May 27, 2019. This paper will be full based on Computer test. Results of the JEE Advanced 2019 will be released in June.